Respuesta :
The molar mass of Al₂(CO₃)₃is 233.99 g/mol
It means 233.99 grams of Al₂(CO₃)₃ are in one mole
And moles in 47.6 g = 47.6/233.99 = 0.203 moles
Now we know that we have 0.203 moles of Al₂(CO₃)₃
In one mole of Al₂(CO₃)₃, we have 3 moles of carbon
To find the number of moles of carbon in a 0.203 moles of Al₂(CO₃)₃, we
must multiply this by the 3 moles of carbon
0.203 x 3 = 0.609 moles of carbon
Within one mole of carbon, we have 6.022 x 10²³ atoms. So, to find the amount of atoms within 0.609 moles of carbon, we must
multiply the 0.609 moles by 6.022 x 10²³ atoms.
So, the number of carbon atoms present in 47.6g of
Al₂(CO₃)₃ = 0.609 x 6.022 x 10²³ = 3.667 x 10²³ atoms.
[tex]\boxed{3.667\times10^{23}\text{ atoms}}[/tex] of carbon are present in 47.6 g of [tex]\text{Al}_2\left(\text{CO}_3_\right)_3[/tex].
Further Explanation:
Firstly, moles of [tex]\text{Al}_2\left(\text{CO}_3_\right)_3[/tex] that are present in 47.6 g of [tex]\text{Al}_2\left(\text{CO}_3_\right)_3[/tex] are to be calculated. This is done with the help of formula mentioned below.
The formula to calculate moles of [tex]\text{Al}_2\left(\text{CO}_3_\right)_3[/tex] is as follows:
[tex]\text{Moles of Al}_2\left(\text{CO}_3_\right)_3=\dfrac{\text{Mass of Al}_2\left(\text{CO}_3_\right)_3}{\text{Molar mass of Al}_2\left(\text{CO}_3_\right)_3}[/tex] ...... (1)
The mass of [tex]\text{Al}_2\left(\text{CO}_3_\right)_3[/tex] is 47.6 g.
The molar mass of [tex]\text{Al}_2\left(\text{CO}_3_\right)_3[/tex] is 233.99 g/mol.
Substitute these values in equation (1).
[tex]\begin{aligned}\text{Moles of Al}_2\left(\text{CO}_3_\right)_3&=\dfrac{\text{47.6 g}}{\text{233.99 g/mol}}\\&=\text{0.203 mol}\end{aligned}[/tex]
From the calculated moles of [tex]\text{Al}_2\left(\text{CO}_3_\right)_3[/tex], moles of carbon that are present in [tex]\text{Al}_2\left(\text{CO}_3_\right)_3[/tex] can be calculated.
As is evident from the chemical formula of [tex]\text{Al}_2\left(\text{CO}_3_\right)_3[/tex], one mole of compound contains two moles of aluminum, three moles of carbon and six moles of oxygen in it.
Since one mole of [tex]\text{Al}_2\left(\text{CO}_3_\right)_3[/tex] contains three moles of carbon in it, number of moles of carbon in 0.203 moles of [tex]\text{Al}_2\left(\text{CO}_3_\right)_3[/tex] can be calculated as follows:
[tex]\begin{aligned}\text{Moles of C}&=(\text{0.203 mol})\left(\dfrac{\text{3 mol}}{\text{1 mol}}\right)\\&=\text{0.609 mol}\end{aligned}[/tex]
In accordance with statement of Avogadro's law, one mole of any substance contains [tex]{6.022\times 10^{23} \text{ particles}}[/tex]. Since one mole of carbon contains [tex]{6.022\times 10^{23} \text{ atoms}}[/tex] of carbon, number of carbon atoms in 0.609 moles of carbon can be calculated as follows:
[tex]\begin{aligned}\text{Atoms of C}&=(\text{0.609 mol})\left(\dfrac{{6.022\times 10^{23} \text{ atoms}}}{\text{1 mol}}\right)\\&=3.667\times10^{23}\text{ atoms}\end{aligned}[/tex]
Learn more:
1. How many moles of Cl are present in 8 moles of [tex]\text{CCl}_4[/tex] ? https://brainly.com/question/3064603
2. Calculate the moles of ions in HCl solution: https://brainly.com/question/5950133
Answer details:
Grade: High School
Subject: Chemistry
Chapter: Mole concept
Keywords: carbon, atoms, mole, molar mass, mass, Al2(CO3)3, 233.99 g/mol, 47.6 g, 0.203 mol, one mole, three moles, C, 0.609 mol, 3.667*10^23 atoms, Avogadro's law.
