contestada

The frequency of an autosomal recessive gene is 0.4. Then what will be the frequency of heterozygotes in progeny among 4000 individual ?
A. 2000

B. 1920

C. 2400

D. 1600

Respuesta :

Answer: B. 1920

Explanation:

To calculate the frequency of heterozygotes among 4000 individuals, we use the Hardy-Weinberg equation:

2pq = frequency of heterozygotes

Given that the frequency of the autosomal recessive gene is 0.4, we can substitute this value into the equation:

2pq = 2 * (0.4) * (1 - 0.4) = 2 * 0.4 * 0.6 = 0.48

The value of 2pq represents the frequency of heterozygotes in the population.

Now, to find the number of heterozygotes in the progeny among 4000 individuals, we multiply the frequency (0.48) by the total number of individuals (4000):

0.48 * 4000 = 1920

Therefore, the frequency of heterozygotes in the progeny among 4000 individuals is 1920

Otras preguntas