Respuesta :

Answer:

318.495m²

Step-by-step explanation:

Yoy can split this problem into three problems where each subproblem demands you find the area of a polygon.

Let A = A1 + A2 + A3 where,

A1 is the area of the bottom rectangle (area = base*height) with sides 20.4m and 9.8m. This area is 20.4m*9.8m = 199.92m²

A2 is the area of the rectangle (area = base*height) at the top left with sides 7.5m and (18.3m - 9.8m = 8.5m). This area is 7.5m*8.5m = 63.75m²

A3 is the area of the remaining triangle (area = base*height/2). The base of the triangle is 12.9m (=20.4m-7.5m) and the height is 8.5m (=18.3m-9.8m) giving the area 12.9*8.5m/2 = 54.825m².

Summing the three areas you get 199.92 m² + 63.75m² + 54.825m² = 318.495m²

Answer:

318.495 m²

Step-by-step explanation:

The allotment can be modelled as a rectangle with its top right corner cut off.

The width (w) and length (l) of the rectangle are:

[tex]\sf w = 18.3\; m[/tex]

[tex]\sf l = 20.4 \;m[/tex]

The base of the triangle (b) is the difference between the top and bottom edges of the allotment:

[tex]\sf b = 20.4 \;m - 7.5 \;m[/tex]

[tex]\sf b = 12.9 \;m[/tex]

The height of the triangle (h) is the difference between the left and right edges of the allotment:

[tex]\sf h = 18.3 \;m - 9.8 \;m[/tex]

[tex]\sf h = 8.5 \;m[/tex]

To find the area of the allotment, we subtract the area of the cut-off triangular corner from the area of the rectangle.

Since the area of a rectangle is the product of its width and length, and the area of a triangle is half the product of its base and height, then area of the allotment can be calculated as follows:

[tex]\begin{aligned}\textsf{Area of allotment}&= \textsf{Area of rectangle} - \textsf{Area of triangle}\\\\&= \sf (w \times l) -\left(\dfrac{1}{2}\times b\times h\right)\\\\&= \sf (18.3\; m \times 20.4\; m) - \left(\dfrac{1}{2}\times 12.9\; m\times 8.5 \;m\right)\\\\&= \sf 373.32 \;m^2 - 54.825 \;m^2\\\\&= \sf 318.495\; m^2\end{aligned}[/tex]

Therefore, the area of the allotment is 318.495 m².

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