A 28-inch board is to be cut into three pieces so that the second piece is twice as long as the first piece and the third piece is 4 times as long as the first piece. If x represents the length of the first piece fine the length of all three pieces

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Answer:

Let's break down the problem using the information given:

Let x = length of the first piece

According to the problem:

The second piece is twice as long as the first piece, so its length is 2x.

The third piece is four times as long as the first piece, so its length is 4x.

The sum of the lengths of all three pieces should equal the total length of the board, which is 28 inches:

x + 2x + 4x = 28

(1x) + (2x) + (4x) = 28

7x = 28

x = 28 / 7

x = 4

So, the length of the first piece (x) is 4 inches.

The length of the second piece is 2 times the length of the first piece: 2 * 4 = 8 inches.

The length of the third piece is 4 times the length of the first piece: 4 * 4 = 16 inches.