Answer:
[tex] \dfrac{7 + 3^2 - 2 \cdot 5}{4 - 1 \cdot 2} = \dfrac{3}{4} + \dfrac{1}{8} \div \dfrac{1}{8} - 2^2 [/tex]
Step-by-step explanation:
[tex] \dfrac{7 + 3^2 - 2 \cdot 5}{4 - 1 \cdot 2} = [/tex]
[tex] = \dfrac{7 + 9 - 10}{4 - 2} [/tex]
[tex] = \dfrac{16 - 10}{2} [/tex]
[tex] = \dfrac{6}{2} [/tex]
[tex] = 3 [/tex]
[tex] \dfrac{3}{4} + \dfrac{1}{8} \div \dfrac{1}{8} - 2^2 = [/tex]
[tex] = \dfrac{6}{8} + \dfrac{1}{8} \times \dfrac{8}{1} - 4 [/tex]
[tex] = \dfrac{7}{8} \times \dfrac{8}{1} - 4 [/tex]
[tex] = \dfrac{7}{8} \times \dfrac{8}{1} - 4 [/tex]
[tex] = 7 - 4 [/tex]
[tex] = 3 [/tex]
Both expressions equal 3.
[tex] \dfrac{7 + 3^2 - 2 \cdot 5}{4 - 1 \cdot 2} = \dfrac{3}{4} + \dfrac{1}{8} \div \dfrac{1}{8} - 2^2 [/tex]
