To find the x-intercepts and y-intercepts of the equation 9x^2 + 4y = 36, we can set each variable equal to zero and solve for the other variable.
To find the x-intercepts, we set y = 0 and solve for x:
9x^2 + 4(0) = 36
9x^2 = 36
Dividing both sides by 9 gives us:
x^2 = 4
Taking the square root of both sides, we get:
x = ±2
So, the x-intercepts are x = 2 and x = -2.
To find the y-intercepts, we set x = 0 and solve for y:
9(0)^2 + 4y = 36
0 + 4y = 36
4y = 36
Dividing both sides by 4 gives us:
y = 9
Therefore, the y-intercept is y = 9.
In summary:
- The x-intercepts are x = 2 and x = -2.
- The y-intercept is y = 9.
