In parallelogram ABCD, if side BE = 3x+2, side BD = 8x-4, and side AE = 4x-2,
What is the length of side AC?

Also

If angle CBE is 41 degrees, Angle ABE is 69 degrees and angle DAE is 26 degrees,
What is the measure of angle CAB?

Respuesta :

Step-by-step explanation:

To find the length of side AC, we need to use the fact that opposite sides of a parallelogram are equal in length. In this case, side BE is opposite to side AD, and side BD is opposite to side AE.Since BE = AD, we can set up the equation:3x + 2 = 8x - 4Simplifying the equation, we get:6 = 5xDividing both sides by 5, we find:x = 6/5Now we can substitute this value of x into the expressions for the lengths of the sides:BE = 3(6/5) + 2 = 18/5 + 2 = 28/5BD = 8(6/5) - 4 = 48/5 - 4 = 28/5AE = 4(6/5) - 2 = 24/5 - 2 = 14/5Since AC is opposite to BD, we have AC = BD = 28/5.Therefore, the length of side AC is 28/5.To find the measure of angle CAB, we can use the fact that opposite angles in a parallelogram are equal. In this case, angle CBE is opposite to angle DAE, and angle ABE is opposite to angle CAB.Since angle CBE is 41 degrees and angle DAE is 26 degrees, we can find angle CAB by subtracting these two angles from 180 degrees (since the sum of the angles in a triangle is 180 degrees):Angle CAB = 180 - 41 - 26 = 113 degrees.Therefore, the measure of angle CAB is 113 degrees.