Respuesta :
To determine the number of nitrogen atoms in the given amount of a compound, we need to know the number of moles of nitrogen. In order to come to this, its is important tht we know the chemical formula of the compound which would be Cu(NO3)2 (molar mass = 187.56 g/mol). When we obtain the moles of nitrogen, we use Avogadro's number to convert the number of moles to atoms.
Moles Cu(NO3)2 = 10.2 g Cu(NO3)2 ( 1 mol / 187.56 g ) = 0.0544 mol
Moles N = 0.0544 mol Cu(NO3)2 ( 2 mol N / mol Cu(NO3)2 ) = 0.109 mol
Atoms N = 0.109 mol N ( 6.022 x20^23 atoms N / mol N ) = 6.55x10^22 atoms N
Moles Cu(NO3)2 = 10.2 g Cu(NO3)2 ( 1 mol / 187.56 g ) = 0.0544 mol
Moles N = 0.0544 mol Cu(NO3)2 ( 2 mol N / mol Cu(NO3)2 ) = 0.109 mol
Atoms N = 0.109 mol N ( 6.022 x20^23 atoms N / mol N ) = 6.55x10^22 atoms N
We have that from the Question"How many nitrogen atoms are in 10.2 g of copper(ii) nitrate?" it can be said that nitrogen atoms in 10.2 g of copper(ii) nitrate are
- aN=6.55x10^22 atoms of N
From the Question we are told
How many nitrogen atoms are in 10.2 g of copper(ii) nitrate?
Generally the equation for copper(ii) nitrate is mathematically given as
Cu(NO3)2
Therefore
For 10.2 g of copper(ii) nitrate
to find moles
Moles Cu(NO3)2 = 10.2 g Cu(NO3)2
0.054mol = 10.2 g Cu(NO3)2
Therefore
moles of N in Cu(NO3)2= 0.054mol *2
moles of N in Cu(NO3)2=0.109mol
Hence
atoms of Nitrogen N
aN=0.109*6.022 x20^23
aN=6.55x10^22 atoms of N
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