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An electron has a constant acceleration of +3.3 m/s2. at a certain instant its velocity is +8.6 m/s. what is its velocity (a) 2.3 s earlier and (b) 2.3 s later?

Respuesta :

Ferraz
Hello!


The velocity function is:

[tex]\mathsf{V = V_0 + at}\\ \\ \mathsf{V = 8.6 +3.3t}[/tex]


a) 2.3 s earlier, we can make t = -2.3 s, in relation to our initial time:

[tex]\mathsf{V = 8.6 + 3.3\cdot(-2.3)}\\ \\ \mathsf{V = 8.8-7.59}\\ \\ \boxed{\mathsf{V = 1.21 \ m/s}}[/tex]

b) Now we can make t = 2.3 s:

[tex]\mathsf{V = 8.6 + 3.3\cdot2.3}\\ \\ \mathsf{V = 8.6 + 7.59}\\ \\ \boxed{\mathsf{V = 15.59 \ m/s}}[/tex]

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