Determine and state an equation of the line perpendicular to the line 5x + 4y=10 and passing through the point (5,12)

Respuesta :

To determine the equation of the line perpendicular to this line, we can first put the equation of the line in slope-intercept form by moving the 5x to the other side:

5x - 5x + 4y = 10 - 5x

4y = -5x + 10

Next, we divide all sides by 4 to isolate y:

y = -5/4x + 5/2

Now, we must implement the opposite reciprocal principle to obtain the slope of the perpendicular line:

-5/4 ⇒ 4/5

Then, we plug this value into the given point (5,12):

12 = 4/5(5) + b

⇒ 12 = 4 + b

b = 8

Therefore, the equation of the line perpendicular to the line 5x + 4y = 10 is y = 4/5x + 8.