Jasmine and Brenda are selling cheesecakes for a school
fundraiser. Customers can buy pecan cheesecakes and
apple cheesecakes. Jasmine sold 2 pecan cheesecakes
and 8 apple cheesecakes for a total of $146. Brenda sold 4
pecan cheesecakes and 7 apple cheesecakes for a total of
$139. Find the cost each of one pecan cheesecake and
one apple cheesecake.

Respuesta :

Answer: Apple Cheesecakes cost 17 dollars

Pecan Cheesecakes costs  5 dollars

Step-by-step explanation:

We first set
Pecan =p
Apple = a

So we can make the equations necessary to solve this equation.

Jasmine: 2p+8a=146

Brenda: 4p+7a=139

We can solve this by using Elimination Method:

Multiply Jasmine's equation by two to get:

4p+16a=292

From there we can subtract that equation from Brenda's to get rid of the p variable.

Once you subtract them. You should get:

9a= 153

Divide it by 9 to get:

a = 17

Now that we have the a variable, we can plug it in to any of the equations to solve for p. For this example, I'll plug it into Jasmine's.

2p+8(17)=146

2p+136=146

2p=10

p=5

So we now know that Pecan costed 5 dollars per cheesecake and Apples costed 17 dollars per cheesecake

msm555

Answer:

Cost of one pecan cheesecake = $5

Cost of one apple cheesecake = $17

Step-by-step explanation:

Let's denote the cost of one pecan cheesecake as [tex]\sf P[/tex] and the cost of one apple cheesecake as [tex]\sf A[/tex].

According to the given information:

Jasmine sold 2 pecan cheesecakes and 8 apple cheesecakes for a total of $146.

This can be expressed as an equation:

[tex]\sf 2P + 8A = 146 [/tex]

Brenda sold 4 pecan cheesecakes and 7 apple cheesecakes for a total of $139.

This can be expressed as another equation:

[tex]\sf 4P + 7A = 139 [/tex]

Now, we have a system of two equations:

[tex]\sf \begin{cases} 2P + 8A = 146 \\ 4P + 7A = 139 \end{cases} [/tex]

We can solve this system of equations to find the values of [tex]\sf P[/tex] and [tex]\sf A[/tex].

Let's multiply the first equation by 2 to make the coefficients of [tex]\sf P[/tex] in both equations the same:

[tex]\sf \begin{cases} 4P + 16A = 292 \\ 4P + 7A = 139 \end{cases} [/tex]

Now, subtract the first equation from the second:

[tex]\sf 4P + 16A - 4P- 7A = 292 - 139[/tex]

[tex]\sf 9A = 153 [/tex]

Divide by 9:

[tex]\sf \dfrac{ 9A }{9}= \dfrac{153 }{9}[/tex]

[tex]\sf A = 17 [/tex]

Now that we have the value for [tex]\sf A[/tex], substitute it back into one of the original equations.

Let's use the first one:

[tex]\sf 2P + 8(17) = 146 [/tex]

[tex]\sf 2P + 136 = 146 [/tex]

Subtract 136 from both sides:

[tex]\sf 2P + 136 -136 = 146-136 [/tex]

[tex]\sf 2P = 10 [/tex]

Divide by 2:

[tex]\sf \dfrac{ 2P}{2} = \dfrac{10 }{2}[/tex]

[tex]\sf P = 5 [/tex]

So, the cost of one pecan cheesecake ([tex]\sf P[/tex]) is $5, and the cost of one apple cheesecake ([tex]\sf A[/tex]) is $17.