Respuesta :
Good afternoon!
We can see that [tex]\mathsf{2.25\times10^8\ \textless \ 3\times10^8 = c}[/tex]
The index of refraction can be calculated as:
[tex]\mathsf{n = \dfrac{c}{v}}[/tex]
As we noted, [tex]\mathsf{v \ \textless \ c}[/tex] , and therefore:
[tex]\mathsf{\dfrac{v}{v} \ \textless \ \dfrac{c}{v}}\\ \\ \\ \mathsf{\dfrac{c}{v} \ \textgreater \ 1}[/tex]
Beccause n = c/v, we have:
n > 1
B - Is more than 1.
We can see that [tex]\mathsf{2.25\times10^8\ \textless \ 3\times10^8 = c}[/tex]
The index of refraction can be calculated as:
[tex]\mathsf{n = \dfrac{c}{v}}[/tex]
As we noted, [tex]\mathsf{v \ \textless \ c}[/tex] , and therefore:
[tex]\mathsf{\dfrac{v}{v} \ \textless \ \dfrac{c}{v}}\\ \\ \\ \mathsf{\dfrac{c}{v} \ \textgreater \ 1}[/tex]
Beccause n = c/v, we have:
n > 1
B - Is more than 1.