Answer:
'm' is maximized, 'M' is maximized, and 'r' is minimized
Explanation:
Newton's universal law of gravitation states that the force of gravity (F) between two masses (m and M) is directly proportional to the product of their masses and inversely proportional to the square of the distance (r) between their centers. The gravitational constant (G) is a constant of proportionality in this equation.
[tex]\boxed{ \begin{array}{ccc} \text{\underline{Newton's Law of Gravitation:}} \\\\ F = G \dfrac{m_1 m_2}{r^2} \\\\ \text{Where:} \\ \bullet \ F \ \text{is the gravitational force} \\ \bullet \ G \ \text{is the gravitational constant} \\ \bullet \ m_1 \ \text{and} \ m_2 \ \text{are the masses} \\ \bullet \ r \ \text{is the distance between the masses} \end{array}}[/tex]
[tex]F \propto mM \text{ or } F \propto \dfrac{1}{r^2}[/tex]
Thus, the force of gravity is maximized when 'm' is maximized, 'M' is maximized, and 'r' is minimized.
