Answer:
Explanation:
To determine the released activity of Cs-137 after 27 years, we can use the formula for radioactive decay:
A = A0 * (1/2)^(t / T),
where:
A is the final activity after time t,
A0 is the initial activity,
t is the time elapsed,
T is the half-life of the radioactive substance.
In this case, the initial activity A0 is given as 6 x 10^6 Ci, the time elapsed t is 27 years, and the half-life T is 30 years.
Plugging in the values into the formula, we get:
A = (6 x 10^6) * (1/2)^(27 / 30)
Calculating this expression, we find that the released activity after 27 years is approximately:
A = 2.221 x 10^6 Ci
Therefore, the released activity becomes 2.221 x 10^6 Ci after 27 years.
