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What volume of 0.1 M NaOH is required to neutralize 30 mL of 0.1 M HCl?

15 mL
45 mL
30 mL
10 mL
60 mL

Respuesta :

the answer would be 30mL

Answer: The volume of NaOH is 30 mL.

Explanation:

To calculate the concentration of acid, we use the equation given y neutralization reaction:

[tex]n_1M_1V_1=n_2M_2V_2[/tex]

where,

[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is HCl

[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base which is NaOH.

We are given:

[tex]n_1=1\\M_1=0.1M\\V_1=30mL\\n_2=1\\M_2=0.1M\\V_2=?mL[/tex]

Putting values in above equation, we get:

[tex]1\times 0.1\times 30=1\times 0.1\times V_2\\\\V_2=30mL[/tex]

Hence, the volume of NaOH is 30 mL.