Answer:
D
Step-by-step explanation:
given the equation
x² + 2x - 26 = 0 ( add 26 to both sides )
x² + 2x = 26
using the method of completing the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(1)x + 1 = 26 + 1
(x + 1)² = 27 ( take square root of both sides )
x + 1 = ± [tex]\sqrt{27}[/tex] = ± [tex]\sqrt{9(3)}[/tex] = ± ( [tex]\sqrt{9}[/tex] × [tex]\sqrt{3}[/tex] ) = ± 3[tex]\sqrt{3}[/tex]
subtract 1 from both sides
x = - 1 ± 3[tex]\sqrt{3}[/tex]
Then x = - 1 - 3[tex]\sqrt{3}[/tex] is a solution to the equation
