we know that
the equation
[tex]y=ax^{2}[/tex]
describe a vertical parabola with vertex at point [tex](0,0)[/tex]
if [tex]a> 0[/tex] -------> the parabola open Up and the vertex is a minimum
if [tex]a< 0[/tex] -------> the parabola open Down and the vertex is a maximum
in this problem we have
[tex]a> 0[/tex] ---> because is positive (given problem)
so
The vertex is a minimum
therefore
the answer is the option C
Up
