To solve this problem, we make use of the formula of combination.
nCr = n! / r! (n – r)!
where n is the total number of subject teachers and r is the number of subjects r = 1
For the English class n = 3
3C1 = 3! / 1! (3 – 1)! = 3
For the Algebra class n = 4
4C1 = 4! / 1! (4 – 1)! = 4
For the Biology class n = 2
2C1 = 2! / 1! (2 – 1)! = 2
The total number of different schedules would be the product of the three combinations:
total combinations possible = 3 * 4 * 2
total combinations possible = 24
