We have 4 apples, 3 peaches, and 4 pears.
The sample size is 11.
1st selection: apple
The probability of selecting an apple is 4/11.
2nd selection: peach
We now have a sample size of 10, which consists of 3 apples, 3 peaches, and 4 pears.
The probability of selecting a peach is 3/10.
3rd selection: peach
We now have a sample size of 9, which consists of 3 apples, 2 peaches, and 4 pears.
The probability of selecting a peach is 2/9.
Each selection was an independent event. Therefore the overall probability is
(4/11)*(3/10)*(2/9) = 4/165
Answer:
The probability of selecting an apple followed by 2 peaches is 4/165.
This probability is equivalent to 0.024 or 2.4%.
