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Erythrosin17
To keep the object swirling, it should be that the forces are balanced in the system. The tension in the spring should be equal to the force exerted by the object in the circular motion. So,

Tension = Force by the object in circular motion
    where the force is given by Newton's second law of motion
    F = ma 

Acceleration for a circular motion is the squared of the velocity over  the radius of the motion.
   F = m (v^2) / r

Thus, tension would be

Tension = mv^2 / r
Tension = 2 kg ( 3 m/s)^2 / 2.5 m
Tension = 7.2 kg m/s^2 or 7.2 N

The tension in qa horizontal string that whirls which moves with speed of 3 m/s on an icy surface is 7.2 N.

What is tension in the string due to circular motion?

Tension is the pulling force carried by the flexible mediums like ropes, cables and string. Tension in the string due to circular motion can be calculated as,

[tex]T=\dfrac{mv^2}{r}[/tex]

Here, (m) is the mass of the object, (v) is the velocity and (r) is the radius of the circular path.

The tension in qa horizontal string has to be calculated. The mass of the toy is 2-kg and the whirl has circle of radius 2.5 m

As the whirl moves at 3 m/s on an icy surface. Thus, the tension on the string can be found out using the above formula by plug in the values as,

[tex]T=\dfrac{(2)(3)^2}{2.5}\\T=7.2\rm N[/tex]

Hence, the tension in qa horizontal string that whirls which moves with speed of 3 m/s on an icy surface is 7.2 N.

Learn more about the tension in the string here;

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