Respuesta :
Given that an average human has a heart rate of 70 beats per minute and if one is to have a 70 year life span, the number of times it will beat is 2,575,440,000 times. This was computed by multiply 70 years by 365 days/year x 24 hours/day x 60 minutes/hour x 70 beats/min. Thus, the heart will beat numerous times before it finally stops.
Answer : The number of beats (N) in the lifetime is [tex]2.6\times 10^9[/tex] beats.
Explanation :
First we have to determine the life time (T) of the person in the unit of minutes.
T = 70 year = (70 × 365 × 24 × 60) minutes
Conversions used :
1 year = 365 days
1 day = 24 hours
1 hour = 60 minutes
As we are given the rate (R) of the heart beat is, 70 beats/minutes.
R = 70 beats/minutes
Now we have to determine the number of beats (N) in the lifetime.
N = RT
N = (70 beats/minutes) × (70 × 70 × 365 × 24 × 60) beats
N = [tex]2.6\times 10^9[/tex] beats
Therefore, the number of beats (N) in the lifetime is [tex]2.6\times 10^9[/tex] beats.