By definition, the unit vector of v = (a,b) is
[tex]\hat{v} = \frac{\vec{v}}{|v|} [/tex]
Therefore,
The unit vector of v₁ = (3,5) in the direction of |v₁| s
(3,5)/√[3² + 5²]
= (3,5)/√34
The unit vector of v₂ in the direction of |v₂| is
(-4,7)/√[(-4)² + 7²]
= (-4,7)/√65
Answer:
The unit vector of v₁ in the direction of |v₁} is [tex]( \frac{3}{\sqrt{34}} , \frac{5}{\sqrt{34}} )[/tex]
The unit vector of v₂ in the directin of |v₂| is
[tex]( \frac{-4}{\sqrt{65}} , \frac{7}{\sqrt{65}} )[/tex]
