Refer to the diagram shown below.
The velocity of the rain relative to the boy is given by
[tex]\vec{V}_{r/b} = \vec{V}_{r} - \vec{V}_{b}[/tex]
in a vectorial sense as shown in the figure.
Given:
Vr = 3.3 m/s
Vb = 5 m/s
Use the Pythagorean to obtain
Vr/b = √(3.3² + 5²) = 6 m/s
The angle that Vr/b makes with due east is
θ = tan⁻¹ (3.3/5) = 33.4°
Answer:
The velocity of the rain with respect to the boy is 6 m/s.
The direction of the rain is 33.4° north of due east.
