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Consider ADEF in the figure below.
The perpendicular bisectors of its sides are XW, YW, and ZW. They meet at a single point W.
(In other words, W is the circumcenter of ADEF.)
Suppose YW = 24, DE=128, and FW = 74.
Find EY, DW, and ZE.
Note that the figure is not drawn to scale.
Check
D
10
E
W
X
Y
F
EY
DW
ZE

Consider ADEF in the figure below The perpendicular bisectors of its sides are XW YW and ZW They meet at a single point W In other words W is the circumcenter o class=

Respuesta :

varshaoman2020

Answer:

Let's find the values:

1. **EY (EY = YW):**

\(EY = YW = 24\)

2. **DW (DW = DE / 2):**

\(DW = \frac{DE}{2} = \frac{128}{2} = 64\)

3. **ZE (ZE = FW / 2):**

\(ZE = \frac{FW}{2} = \frac{74}{2} = 37\)

The values are:

- \(EY = 24\)

- \(DW = 64\)

- \(ZE = 37\)

Please note that the check values D = 10, F = 10, and X = 24 are not provided, but you can verify these based on the relationships in the figure.

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