The solution would be like this for this specific problem:
a = v2r (formula for magnitude of acceleration)
a = 6.25 × 105 ms^-2
Use V^2 = Vo^2 + 2a (X - Xo)
We know that the meteorite travels at a speed of .2m, but it stops
moving so V^2 has a 0 value. Also, you’re told that Vo is 500 and Xo is 0.
0 = 500^2 + 2a (.2 - 0)
-250000 = .4a
a = -625000. I thought that a should have been negative since it was
slowing down, but it told me to change signs so a should be a = 625000 m/s^2
