Sulfur dioxide has a molecular formula of SO2. The balanced
chemical reaction leading to this isas shown below:
S + O2 --->
SO2
Therefore this means that 1 mole of sulfur and 1 mole of O2
reacts to form 1 mol of sulfur dioxide.
Assuming 1 mol of O2 and 1 mol of S for the sake of
calculation, therefore:
mass oxygen, O = (1 mol O2) (2 mol O/ 1 mol O2) (16 g O/
mol O) = 32 g O
mass sulfur, S = 1 mol (32 g / mol) = 32 g
Therefore the ratio of O to S is:
O:S = 32 g O / 32 g S = 1 g O2/ 1 g S
Hence, there is 1 g of oxygen per 1 g of sulfur in sulfur
dioxide.
