If we draw a Venn diagram, we can see that the 0.55 is
the intersection of probability owning a car and probability owning a computer.
To solve for the probability that the student owns neither, we need to solve
first for other variables.
The probability that a student owns a car but not a
computer is:
P (owns a car but not computer) = 0.65 – 0.55 = 0.10
The probability that a student owns a computer but not a car
is:
P (owns a car but not computer) = 0.82 – 0.55 = 0.27
Therefore the probability of owning neither is:
P (own neither) = 1 – 0.10 – 0.27 – 0.55
P (own neither) = 0.08
Therefore there is a 8% probability that the student owns
neither a car or a computer.
