lori0908
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The width of this rectangle is measured as 19.4mm correct to 1 decimal place.
What is the lower bound for the area of the rectangle?

Respuesta :

Abu99
We need to find the shortest possible width and length to get the smallest possible area.
To get the boundaries for 19.4, we go on to the next significant figure (the hundredths) and ± 5 of them.
The boundaries are, therefore: 19.35 - 19.45
As for the length, we can see they've added 5 units as the measurement is correct to 2 sig' figures, which is the tens.
And so, if we do as we did before, we go to the next sig' figure (the units) and ± 5 of them, we get the boundaries to be 365 - 375.

Now, we just multiply the lower bounds of the length and width to get the minimal/lower-bound area:
365 * 19.35 = 7062.75 mm²
MrRoyal

The area of shape is the amount of space it can occupy

The lower bound for the area is [tex]7062.75mm^2[/tex]

From the complete question, we have:

[tex]Width = 19.4mm[/tex]

[tex]Length =370mm[/tex]

First, we get the lower bound of the dimensions

The upper bound for length in the complete question is:

[tex]Length = 375mm[/tex]

This means that, the lower bound would be

[tex]Length = 365mm[/tex]

The upper bound for width in the complete question is:

[tex]Width = 19.45mm[/tex]

This means that, the lower bound would be

[tex]Width = 19.35mm[/tex]

So, the area of the rectangle is:

[tex]Area = Length \times Width[/tex]

Using the lower bound dimensions, we have:

[tex]Area = 365mm \times 19.35mm[/tex]

[tex]Area = 7062.75mm^2[/tex]

Hence, the lower bound of area is [tex]7062.75mm^2[/tex]

Read more about areas at:

https://brainly.com/question/24798835

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