As k2o dissolves in water, the oxide ion reacts with water molecules to form hydroxide ions. write the molecular and net ionic equations for this reaction.

Respuesta :

As the description above says, the molecular reaction is:

K₂O(aq) + H₂O(l) → 2 KOH(aq)

Make sure that you balance the reaction to obey the Law of Definite Proportions. This is done by making sure that the number of atoms of a certain element is equal in bot the reactant and product side of the reaction. 

To obtain the ionic equation, express all of the ionic forms of the aqueous solutions:

 K⁺(aq) + O²⁻(aq) + H₂O(l) → K⁺(aq) + 2 OH⁻(aq)

The net ionic reaction is obtained when you delete the spectator ions: the ions that appear at both sides of the reaction. Thus, the net ionic reaction is

O²⁻(aq) + H₂O(l) → + 2 OH⁻(aq)

Molecular equation for dissolution of [tex]\text{K}_2\text{O}[/tex] in water is as follows:

[tex]\boxed{\text{K}_2\text{O}(aq)+\text{H}_2\text{O}(l)\rightarrow2\text{KOH}(aq)}[/tex]

The net ionic equation for dissolution of [tex]\text{K}_2\text{O}[/tex] in water is as follows:

[tex]\boxed{\text{O}^{2-}(aq)+\text{H}_2\text{O}(l)\rightarrow2\text{OH}^-(aq)}[/tex]

Further Explanation:

Chemical reactions indicate the conversion of one type of chemical substances into another and are characterized by chemical change. In this process, bonds between reactants are broken and new bonds are formed, leading to formation of products.

Following are the types of equations used to write chemical reactions:

1. Molecular equation

2. Total ionic equation

3. Net ionic equation

In molecular equations, the undissociated form of both reactants and products are mentioned. As is evident from its name, total ionic equations involve all types of ions involved in the reactions. But in net ionic equations, only spectator ions are written.

In this reaction, [tex]\text{K}_2\text{O}[/tex] reacts with water to form KOH. The phases of [tex]\text{K}_2\text{O}[/tex], [tex]\text{H}_2\text{O}[/tex] and KOH are aqueous, liquid and aqueous phase respectively. Unbalanced molecular equation for this reaction is given as follows:

[tex]\text{K}_2\text{O}(aq)+\text{H}_2\text{O}(l)\rightarrow\text{KOH}(aq)[/tex]

Number of atoms of K  and H are not same on both sides of reaction. In order to balance this reaction, multiply KOH by 2. Therefore balanced molecular equation becomes,

[tex]\text{K}_2\text{O}(aq)+\text{H}_2\text{O}(l)\rightarrow2\text{KOH}(aq)[/tex]

In order to write ionic equation, compounds that exist in aqueous phases are dissociated into respective ions. Therefore total ionic equation becomes,

[tex]\text{2K}}^{+}(aq)+{\text{O}^{2-}(aq)+\text{H}_2\text{O}(l)\rightarrow2{\text{K}^{+}(aq)+2\text{OH}^-(aq)[/tex]

In order to write net ionic equation, common [tex]\text{K}^+[/tex] ions on both sides of equation are cancelled. Therefore net ionic equation becomes,

[tex]\text{O}^{2-}(aq)+\text{H}_2\text{O}(l)\rightarrow2\text{OH}^-(aq)[/tex]

Learn more:

1. Balanced chemical equation: https://brainly.com/question/1405182

2. Identification of all of the phases of the reaction: https://brainly.com/question/8926688

Answer details:

Grade: High School

Subject: Chemistry

Chapter: Chemical reactions and equations

Keywords: chemical reactions, reactants, products, molecular equations, net ionic equation, K2O, water, O2-, OH-, KOH, ions, conversion.