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A horizontal force of 200 n is applied to move a 55-kg cart (initially at rest) across a 10-m level surface. what is the final kinetic energy of the cart?

Respuesta :

Erythrosin17
Kinetic energy is the energy that is possessed by an object that is moving. It is calculated by one-half the product of the mass and the square of the velocity of the object. We need to determine the velocity of the cart that is moving. 

First, we use Newton's Second Law of motion;
Force = ma 
200 = 55a 
a = 3.64 m/s^2 

Then, from the kinematic equation we calculate the velocity;
v^2 = v0^2 + 2ax

where v is the final velocity, v0 is the initial veocity (zero since it initially start at zero), a is the acceleration ( 3.64 m/s^2) and x is the distance traveled.

v^2 = 0^2 + 2 (3.64) (10) 
v^2 = 72.73 m^2 / s^2
v = 8.53 m / s 

KE = mv^2 / 2
KE = 1/2 (55) (8.53^2) 
KE= 2000 J
asuwafohjames

The Kinetic energy of the cart is 2000 J.

The kinetic energy of the cart can be calculated using the formula below.

Formula:

  • E.K = Fd............ Equation 1

Where:

  • E.K = Kinetic energy of the cart
  • F = Force applied to the cart
  • d = Distance

From the question,

Given:

  • F = 200 N
  • d = 10 m

Substitute these values into equation 1

  • E.K = 200(10)
    E.K = 2000 J

Hence, The Kinetic energy of the cart is 2000 J.

Learn more about Kinetic energy here: https://brainly.com/question/20658056


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