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A 2.747g sample of manganese metal is reacted with excess hcl gas to produce 3.22l hydrogen gass at 373 k and 0.951 atm and a manganese chloride compound (mnclx). determine the formula of the manganese chloride produced by this reaction.

Respuesta :

1. Find moles! In this case, since we are dealing with H2 gas, we will be using PV=nRT (Where P is pressure, V is volume in liters, n is moles, R is the gas constant specific for the pressure unit and T is temp in Kelvin).
(0.951 atm)(3.22L)=n(.082057)(373K)  
3.062=30.607n  n=0.100 moles H2

Mn (s) +HCl (g)-->  H2 (g)+ Mn(Cl#)

The ratio of HCl to H2 must be 2:1 (Although we do not know the exact number, the ratio must be that so the actual equation can be balanced)
0.100 moles H2* (2 mol HCl/1molH2)=0.200 moles HCl 
0.200 moles HCl * (1mol Cl-/1molHCl)=0.200 moles of chlorine 
2. Find moles of manganese
2.747g Mn * (1 mol Mn/54.938g Mn)=0.05000 moles Mn

3. Mole Ratio
0.05000 moles Mn/0.200 moles chlorine=0.25 (A ratio of 1/4)
The formula should be MnCl₄

mahima6824soni

The formula of manganese chloride produced by the reaction is [tex]MnCl_4[/tex].

What is manganese chloride?

It is a dichloride salt of manganese, it is present in anhydrous form.

Mass of manganese is 2.747g

Hydrogen gas is 3.22l

Pressure- 0.951 atm

Temperature- 373 K

Step 1. From the formula

PV = nRT

Putting the values

(0.951 atm)(3.22L)=n(.082057)(373K)  

3.062 = n30.607

n = 0.100 moles

The reaction is

[tex]\rm Mn (s) +HCl (g) = H_2 (g)+ Mn(Cl)[/tex]

The ratio of [tex]HCl\; to\; H_2[/tex]

2:1

Hydrogen has 2 molecules, thus,

[tex]0.100\; moles \;H_2 \times (2 mol HCl/1mol\;H_2)=0.200\; moles\; HCl[/tex]

[tex]0.200 \;mol\; HCl \times (1mol Cl-/1molHCl)=0.200 mol\; of\; chlorine[/tex]

Step 2. Calculate the moles of manganese

[tex]\rmNumber\;of \;moles= \dfrac{mass}{molar\;mass}\\\\\\\rmNumber\;of \;moles= \dfrac{2.747g Mn}{54.938g Mn} = 0.05000\; mol[/tex]

Step 3. Calculate the mole ratio of  manganese

[tex]\dfrac{0.05000\; mol\; Mn}{0.200\; mol\; cl} = 0.25[/tex]

Thus, the formula of manganese chloride produced by the reaction is [tex]MnCl_4[/tex].

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