Let initially there are 10 molecules of O2 and 3 molecules of C3H8 present
The reaction will be
C3H8(g) + 5O2(g) ----> 3CO2(g) + 4H2O
so here oxygen molecules are limiting as for 3 molecules of C3H8 we need 15 molecules of O2
now the given 10 molecules of O2 will react with only 2 molecules of C3H8 and they will form six molecules of CO2 and 8 molecules of H2O
Hence answer is
molecules of CO2 formed = 6
Molecules of H2O formed = 8
molecules of C3H8 left = 1
molecules of O2 left = 0
Molecules of CO₂, H₂O, C3H8, and O₂ will be present if the reaction goes to completion are
0 molecules C3H8
0 O₂ molecules
3 and CO₂ molecules
4 H₂O molecules
The reaction equation is the chemical formula of reagents and product substances
The reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.
Steps in equalizing the reaction equation:
• 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c, etc.
• 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product
• 3. Select the coefficient of the substance with the most complex chemical formula equal to 1
The reaction of the combustion of hydrocarbons with oxygen produces CO₂ and H₂O (water vapor). can use steps:
Balancing C atoms, H and last atoms O atoms
Equivalent reaction equation, if the number of atomic substances of the reactor is the same as the product substance
The reaction coefficient also shows the ratio of moles, volumes or molecules of substances involved in the reaction
Complete combustion of Hydrocarbons with Oxygen will be obtained by CO₂ and H₂O compounds.
If O₂ is insufficient there will be incomplete combustion resulting in CO and H₂O
In perfect combustion of propane(C3H8) and oxygen (O₂), propane and oxygen will be converted entirely into CO₂ and H₂O at the end of the reaction
Propane and oxygen reactions:
C₃H₈ + O₂ ---> CO₂ + H₂O
We equalize first by giving coefficients a, b and c
C₃H₈ + aO₂ ---> bCO₂ + cH₂O
C = left 3, right b -> b = 3
H = left 8, right 2c ---> c = 4
O = left 2a , right 2b + c
2a = 2b+c
2a = 2 . 3 + 4
2a = 10
a = 5
So the equivalent reaction equation =
C₃H₈ + 5O₂ ---> 3CO₂ + 4H₂O
The comparison of the coefficients shows that: 1 C3H8 molecule reacts with 5 molecule O₂ produces 3 molecules of CO₂ and 4 molecules of H₂O
So the complete combustion of ethanol at the end of the reaction composition:
0 molecules C3H8
0 O₂ molecules
3 CO₂ molecules
4 H₂O molecules
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Keywords : combustion, propane, molecules
