contestada

Consider a uniform solid sphere of radius R and mass M rolling without slipping. Which form of its kinetic energy is larger, translational or rotational?

Respuesta :

Erythrosin17
Translational kinetic energy is equal to one half the product of mass andthe square of the linear velocity. Rotational kinetic energy, on the other hand, is one half the product of the mass of the object in circular motion and the square of the angular velocity where angular velocity is equal linear velocity divided by the radius of the circular motion. To compare these energies, we do as follows:

KE(t) = 0.5mv^2
KE(r) = 0.5mw^2 = 0.5mv^2/r^2
KE(r) = KE(t)/r^2

From the relation, rotational kinetic energy is 1/r^2 times than the translational kinetic energy. Therefore, translational kinetic energy would be bigger than the rotational kinetic energy.
Martebi

There are different kinds of energy.  The form of the kinetic energy is that translational energy is larger.

What is translational kinetic energy?

This is commonly defined as the energy of motion of a body, that is said to be the same to the work it would do if it were said to be brought to a point of rest.

The translational kinetic energy is known to be one that depends on motion via space, and when there is a rigid body of constant mass, it is said to be the same or equal to the product of half the mass multiplies by the square of the speed.

Learn more about  translational kinetic energy from

https://brainly.com/question/9078768

Otras preguntas