A right rectangular prism has these dimensions: Length 1 1/3 width 5/6 height 2/3 how many cubes of side length 1/6 unit are required to completely pack the prism without any gap or overlap?

Respuesta :

To answer this item, we have to compute for the volume of prism. The equation that allows us to calculate the volume is,
                    Vp = L x W x H
where V is volume, L is length, W is width, and H is height. 

Substitute the given values,
                    Vp = (1 1/3)(5/6)(2/3)
                    Vp = 20/27 units cubed

Next, we calculate for the volume of each cube by the equation,
                 Vc = s³
where s is the length of the sides.
                   Vc = (1/6)³ 
                  Vc = 1/216 units cubed

Lastly, to calculate for the number of cubes inside the prism, we divide the volume of prism by the volume of the cube.
                 n = Vp/Vc
                n = (20/27) / (1/216) 
                  n = 160

ANSWER: 160 cubes

Answer:

The number of cubes required is 160.

Step-by-step explanation:

The dimensions of the right rectangular prisms are

l=1\frac{1}{3} \;units

w=\frac{5}{6} \;units

h=\frac{2}{3} \;units

The volume of the right rectangular prism is

V=l\times b\times h.

We substitute the dimensions to get,

V=1\frac{1}{3}\times \frac{5}{6}\times \frac{2}{3}.

We convert the first mixed number to improper fraction,

V=\frac{4}{3}\times \frac{5}{6}\times \frac{2}{3}.

We multiply out to obtain,

V=\frac{40}{54}

V=\frac{20}{27} cubic units.

We need to determine the volume of the cube of side length,

l=\frac{1}{6} units.

The volume of a cube is given by,

V=l^3

This implies that,

V=(\frac{1}{6})^3

This gives us,

V=\frac{1}{216} cubic units.

We now divide the volume of the right rectangular prism by the volume of the cube to determine the number of cubes required.

Number\:of\:cubes=\frac{\frac{20}{27} }{\frac{1}{216} }

We simplify to get,

Number\:of\:cubes=\frac{20}{27} \div \frac{1}{216}

This implies that,

Number\:of\:cubes=\frac{20}{27} \times \frac{216}{1}

Number\:of\:cubes=20\times8

Number\:of\:cubes=160