Answer:
S(-2, 12) lies on the circle
Step-by-step explanation:
Given : Equation of circle : [tex](x + 2)^2 + (y - 3)^2 = 81[/tex]
Point: S(-2, 12)
To Find: Is the given point interior, exterior, or on the circle
Solution :
After substituting the values,
If L.H.S of the given equation is less than R.H.S , So, the given point is interior.
If L.H.S of the given equation is greater than R.H.S , So, the given point is exterior.
If L.H.S =R.H.S , So, the given point is on the circle.
[tex](-2 + 2)^2 + (12 - 3)^2 = 81[/tex]
[tex](0)^2 + (9)^2 = 81[/tex]
[tex]81 = 81[/tex]
Thus L.H.S =R.H.S
Hence the given point S(-2, 12) lies on the circle [tex](x + 2)^2 + (y - 3)^2 = 81[/tex]
