We are given the function: 1 divided by the quantity x minus 2 squared and is asked in the problem to determine the limit of x as x approaches 2 as well as vertical asymptotes if there are any. To find the limit, we just have to substitute the equation with the value of the numerical limit. The equation then becomes, 1/ (x-2)^2 = 1/(2-2)^2 = 1/0 . Any number divided by zero is equal to infinity so the limit is infinity. A vertical asymptote is the value of x in which the denominator becomes zero, that is (x-2)^2 = 0; x = 2. The vertical asymptote is equal to 2.
