Respuesta :

wizard123
[tex]x = r cos \theta \\ \\ y = r sin \theta[/tex]

[tex]x = (-2) cos (\pi/3) = (-2)(\frac{1}{2}) =-1 \\ \\ y=(-2) sin (\pi/3) = (-2)(\frac{\sqrt{3}}{2})=-\sqrt{3}[/tex]

The rectangular coordinates are:
[tex](-1,-\sqrt{3})[/tex]

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