we use quadratic formula for that one
remember that √-1=i
so
for
ax^2+bx+c=0
[tex]x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}[/tex]
so
given
5x^2-6x+2=0
a=5
b=-6
c=2
[tex]x=\frac{-(-6)+/-\sqrt{(-6)^2-4(5)(2)}}{2(5)}[/tex]
[tex]x=\frac{6+/-\sqrt{36-40}}{10}[/tex]
[tex]x=\frac{6+/-\sqrt{-4}}{10}[/tex]
[tex]x=\frac{6+/-2i}{10}[/tex]
[tex]x=\frac{3}{5}+\frac{i}{5}, \frac{3}{5}-\frac{i}{5}[/tex]
