Respuesta :
easy
equation is
f(x)=2ˣ
where x=number of hours elapsed
after 6 hours
f(6)=2⁶=64 bacteria
to solve for 1024
1024=2ˣ
take ln of both sides
ln(1024)=ln(2ˣ)
ln(1024)=x(ln(2))
divide both sides by ln(2)
ln(1024)/ln(2)=x
using calculator
10=x
or you could recognize that
1024=2¹⁰
or keep divising 1024 by 2
10 hours for 1024 bacteria
equation is
f(x)=2ˣ
where x=number of hours elapsed
after 6 hours
f(6)=2⁶=64 bacteria
to solve for 1024
1024=2ˣ
take ln of both sides
ln(1024)=ln(2ˣ)
ln(1024)=x(ln(2))
divide both sides by ln(2)
ln(1024)/ln(2)=x
using calculator
10=x
or you could recognize that
1024=2¹⁰
or keep divising 1024 by 2
10 hours for 1024 bacteria
The bacteria will take 10 hours to be 1024 bacteria.
This example of the bacteria is a case of Exponential Progression, which multiplies itself at a constant rate. This kind of progression is defined by the following expression:
[tex]n = n_{o}\cdot r^{t}[/tex] (1)
Where:
[tex]n_{o}[/tex] - Initial population of the bacteria, no unit.
[tex]n[/tex] - Current population of the bacteria, no unit.
[tex]r[/tex] - Increase rate, no unit.
[tex]t[/tex] - Time, in hours.
Then, if we know that [tex]n_{o} = 1[/tex], [tex]r = 2[/tex] and [tex]n = 1024[/tex], then the time taken by the bacteria is:
[tex]\frac{n}{n_{o}} = r^{t}[/tex]
[tex]\log \frac{n}{n_{o}} = t\cdot \log r[/tex]
[tex]\log n - \log n_{o} = t\cdot \log r[/tex]
[tex]t = \frac{\log n - \log n_{o}}{\log r}[/tex]
[tex]t = \frac{\log 1024-\log 1}{\log 2}[/tex]
[tex]t = 10\,h[/tex]
The bacteria will take 10 hours to be 1024 bacteria.
Please see this question related to Exponential Progression: https://brainly.com/question/4853032