Translate the info given into equations:
A positive integer is 15 less than another -----> x = y - 15
If 4 times the reciprocal of the smaller integer is subtracted from the reciprocal of the larger integer, then the result is − 3/4
------> (1/y) - (4/x) = -3/4
Use substitution, replace 'x' with 'y-15' in 2nd equation
[tex]\frac{1}{y} - \frac{4}{y-15} = -\frac{3}{4} \\ \\ \frac{ (y-15)-4y}{y(y-15)}=-\frac{3}{4} \\ \\ 4(-3y-15) = -3y(y-15) \\ \\ -12y -60 = -3y^2+45y \\ \\ 3y^2-57y-60 = 0 \\ \\ y^2-19y -20 =0 \\ \\ (y-20)(y+1) = 0 \\ \\ y = 20,y=-1[/tex]
We know that both x and y must be positive integers, so y =-1 is not a solution.
If y=20, then x = 20-15 = 5
Final answer:
The pair of integers is (5,20)
