Respuesta :

f(x)=(x^3)/(x-1) has no horizontal asymtote
alright

to find the horizontal assemtote,

if the degree of the denomenator is larger than the degree of the numerator, the horizontal assemtote is 0

if the degrees are the same, divide the coefients of the highest powers

if the degree of the the numerator is larger than the degree of the denomenator, it has no horizontal assemtote



vertical assemtote
get the fraction into simplest form then set the denomenator equal to 0




alright, we want no horizontal assemtote and a vertical assemtote at x=1

x=1
minu1 both sides
x-1=0

that will be the denomenator
and the numerator degree must be greater than denomenator

so
[tex]y=\frac{x^2}{x-1}[/tex] is one possible function