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The perimeter of a rectangle is 38 ft. The length is 9 ft longer than the width. Find the demensions. Write a system of linear equations and solve the resulting system. Let x be length and y be width.

Respuesta :

apologiabiology
P=38
P=2x+2y=2(x+y)
x=9+y



so
38=P=2(x+y)
38=2(x+y)
divide both sides by 2
19=x+y
x=9+y
19=9+y+y
19=9+2y
minus 9 both sides
10=2y
divide by 2
5=y
sub back
x=9+y
x=9+5
x=14


x=14
y=5

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