Respuesta :
[tex]y=\frac{9}{\sqrt{5x+5}}[/tex]
hmm, seems that we can say that the square root thing is the g(x)
I would say
[tex]f(x)=\frac{9}{x}[/tex] and
[tex]g(x)=\sqrt{5x+5}[/tex]
we could also have
[tex]f(x)=\frac{9}{\sqrt{x}}[/tex] and
[tex]g(x)=5x+5[/tex]
or
[tex]f(x)=\frac{9}{\sqrt{x+5}}[/tex] and
[tex]g(x)=5x[/tex]
there are many posibilities
hmm, seems that we can say that the square root thing is the g(x)
I would say
[tex]f(x)=\frac{9}{x}[/tex] and
[tex]g(x)=\sqrt{5x+5}[/tex]
we could also have
[tex]f(x)=\frac{9}{\sqrt{x}}[/tex] and
[tex]g(x)=5x+5[/tex]
or
[tex]f(x)=\frac{9}{\sqrt{x+5}}[/tex] and
[tex]g(x)=5x[/tex]
there are many posibilities
Answer:
f(x)=[tex]\frac{9}{x}[/tex]
g(x)= [tex]\sqrt{5x+5}[/tex]
Step-by-step explanation:
y=[tex]\frac{9}{\sqrt{5x+5} }[/tex]
We have to find f(x) and g(x). There are many possible answers, but we are going to suppose that f(x)=[tex]\frac{9}{x}[/tex]
to obtain y(x) we should have [tex]\sqrt{5x+5}[/tex] in the denominator. We can obtain that by saying that g(x)= [tex]\sqrt{5x+5}[/tex] so f(g(x))=[tex]\frac{9}{sqrt{5x+5}}[/tex]