The
chemical reaction involved in this titration process would be:
2NaOH + H2SO4 = Na2SO4 + 2H2O
To determine the concentration of the NaOH
solution, we need to first calculate for the moles of NaOH that is used up
in the reaction given the amount of H2SO4 solution that is used. We do as
follows:
Moles NaOH = 0.100 M H2SO4 ( .01845 L solution ) ( 2 mol NaOH / 1 mol H2SO4 ) = 3.69x10^-3 mol NaOH reacted
Volume of NaOH = .025 L
Molarity is the number of moles of a solute per
liter of solution. We calculate as follows:
Molarity of NaOH = 3.69x10^-3 mol NaOH / .025 L = 0.1476 M
