1) Calculate the number of moles in 1.15 liter of 0.100 M HNO3 solution.
M = n / V => n = M*V = 0.100M * 1.15 l = 0.115 moles
2) Calculate the mass of 0.115 moles of HNO3
mass = number of moles * molar mass
molar mass of HNO3 = 1.00 g/mol + 14.0 g/mol + 3*16.0g/mol = 63.0 g/mol
mass = 0.115 mol * 63.0g/mol = 7.245 g
3) Calculate the mass of 70.3% HNO3 solution that contains 7.245 grams of HNO3
% = (mass of solute / mass of solution) * 100
=> mass of solution = mass of solute * 100 / % = 7.245 g * 100 / 70.3%
mass of soltuion = 10.3 g.
4) Convert 10.3 grams of HNO3 solution into volume, using density, D
D =mass / Volume => Volume = mass / D
=. Volume = 10.3 g / 1.41 g/cm^3 = 7.30 cm^3
Answer: 7.30 cm^3
