A gas sample contains 4.00 g of ch4. what is the volume of the sample at stp

Hey there !

Molar mass CH4 = 16.04 g/mol

16.04 g ------------------ 22.4 L ( at STP )
4.00 g ------------------- Volume

Volume = 4.00 * 22.4 / 16.04

Volume = 89.6 / 16.04

Volume = 5.586 L

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BarrettArcher BarrettArcher · Answer 2 · 2019-04-18T08:35:33+02:00

Answer : The volume of the gas sample at STP is, 5.6 L

Explanation : Given,

Mass of [tex]CH_4[/tex] = 4 g

Molar mass of [tex]CH_4[/tex] = 16 g/mole

First we have to calculate the mole of [tex]CH_4[/tex]

[tex]\text{Moles of }CH_4=\frac{\text{Mass of }CH_4}{\text{Molar mass of }CH_4}=\frac{4g}{16g/mole}=0.25mole[/tex]

Now we have to calculate the volume of [tex]CH_4[/tex] at STP.

As we know that at STP, 1 mole of gas contains 22.4 L volume of gas

As, 1 mole of gas contains 22.4 L volume of gas sample

So, 0.25 mole of gas contains [tex]0.25\times 22.4L=5.6L[/tex] volume of gas sample

Therefore, the volume of the gas sample at STP is, 5.6 L