Next time please correctly write the equation. I believe in
this case it would be:
x^4 – x – 6 = 0
Correct me if I am wrong though.
Now let us go back in answering this problem. Using
newton’s method of approximation, the value of x2 would be:
x2 = x1 – [f(x1) / f’(x1)]
Since x1 = 1, therefore:
f(x1) = 1^4 – 1 – 6 = - 6
And the 1st derivative of f(x) is f’(x) so:
f’(x) = 4 x^3 – 1
f’(x1) = 4 (1)^3 – 1 = 3
Calculating for x2 now:
x2 = 1 – [- 6 / 3]
x2 = 1 – [- 2]
x2 = 3
