What are the sine, cosine, and tangent of Θ = 3 pi over 4 radians?

sin Θ = square root 2 over 2; cos Θ = negative square root 2 over 2; tan Θ = -1

sin Θ = negative square root 2 over 2; cos Θ = square root 2 over 2; tan Θ = 1

sin Θ = square root 2 over 2; cos Θ = negative square root 2 over 2; tan Θ = 1

sin Θ = negative square root 2 over 2; cos Θ = square root 2 over 2; tan Θ = -1

Question

09-08-2017
Mathematics

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What are the sine, cosine, and tangent of Θ = 3 pi over 4 radians?

sin Θ = square root 2 over 2; cos Θ = negative square root 2 over 2; tan Θ = -1

sin Θ = negative square root 2 over 2; cos Θ = square root 2 over 2; tan Θ = 1

sin Θ = square root 2 over 2; cos Θ = negative square root 2 over 2; tan Θ = 1

sin Θ = negative square root 2 over 2; cos Θ = square root 2 over 2; tan Θ = -1

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jdoe0001 jdoe0001 · Answer 1 · 2017-08-09T00:55:16+02:00

jdoe0001 jdoe0001

09-08-2017

notice the "x" and "y" coordinates

the x-coordinate is well, the cosine value
the y-coordinate is well, the sine value

now the tangent

[tex]\bf tan(\theta)=\cfrac{opposite}{adjacent}=\cfrac{y}{x}\\\\ -------------------------------\\\\ tan(\theta )=\cfrac{\frac{\sqrt{2}}{2}}{-\frac{\sqrt{2}}{2}}\implies tan(\theta )=-1[/tex]

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