Respuesta :
assuming yo meant
4(3b+2)²=64
divide both sides by 4
(3b+2)²=16
sqrt both sides
remember to take positive and negative roots
3b+2=+/-4
minus 2 both sides
3b=-2+/-4
divide by 3
b=(-2+/-4)/3
b=(-2+4)/3 or (-2-4)/3
b=2/3 or -6/3
b=2/3 or -2
A is answer
4(3b+2)²=64
divide both sides by 4
(3b+2)²=16
sqrt both sides
remember to take positive and negative roots
3b+2=+/-4
minus 2 both sides
3b=-2+/-4
divide by 3
b=(-2+/-4)/3
b=(-2+4)/3 or (-2-4)/3
b=2/3 or -6/3
b=2/3 or -2
A is answer
The values that b satisfies in the equation 4(3b +2)² = 64 is:
b = -2/3 or -2.
What is a Quadratic Equation?
A quadratic equation is a form of algebraic expression raised to the second degree.
From the given equation, we have:
4(3b +2)² = 64
4 ((3b + 2)²) = 64
Divide both sides by 4
(3b + 2)²= 16
Taking the square root of both sides
√(3b + 2)² = √16
3b + 2 = ±4
3b = -2±4
b = -2±4/3
b = -2-4/3 or -2+4 /3
b = -6/3 or -2/3
b = -2 or -2/3
Learn more about quadratic equations here:
https://brainly.com/question/17210919