What values of b satisfy 4(3b + 2)2 = 64?
A. b = 2/3 and b = –2
B. b = 2 and b = 10/3
C. b = 2/3 and b = 3
D. b = 2 and b = -10/3

Respuesta :

assuming yo meant
4(3b+2)²=64

divide both sides by 4
(3b+2)²=16
sqrt both sides
remember to take positive and negative roots
3b+2=+/-4
minus 2 both sides
3b=-2+/-4
divide by 3
b=(-2+/-4)/3
b=(-2+4)/3 or (-2-4)/3
b=2/3 or -6/3
b=2/3 or -2


A is answer

The values that b satisfies in the equation 4(3b +2)² = 64 is:

b = -2/3 or -2.

What is a Quadratic Equation?

A quadratic equation is a form of algebraic expression raised to the second degree.

From the given equation, we have:
4(3b +2)² = 64

4 ((3b + 2)²) = 64

Divide both sides by 4

(3b + 2)²= 16

Taking the square root of both sides

√(3b + 2)² = √16

3b + 2 = ±4

3b = -2±4

b = -2±4/3

b = -2-4/3 or -2+4 /3

b = -6/3 or  -2/3

b = -2 or -2/3

Learn more about quadratic equations here:

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