[tex]\bf \textit{arc's length}\\\\
s=\cfrac{\theta \pi r}{180}\qquad
\begin{cases}
r=radius\\
\theta =angle\ in\\
\qquad degrees\\
------\\
r=6\\
s=10
\end{cases}\implies 10=\cfrac{\theta \pi 6}{180}\implies \cfrac{180\cdot 10}{6\pi }=\theta
\\\\\\
\cfrac{300}{\pi }=\theta \implies 95.49^o\approx \theta [/tex]
now, the circle of the clock has 360°, if we divide it by 60(minutes), we get 360/60, just 6° for each minute.
now, if there are 6° in 1 minute, how many minutes in 95.49°?
well, just 95.49/6 or about 15.92 minutes, I take it you can round it up to 16 minutes.
so 16 minutes since noon, so is about 12:16, about time get the silverware for lunch.
